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fastjson将json格式字符串转成list集合

2024-03-31 Web开发

1.gameListStr = "[{"gameId":"1","gameName":"哈哈"},{"gameId":"2","gameName":"呵呵"}]"; 2. List<Game> gameList = JSONObject.parseArray(gameListStr, Game.class);

public class Game { public String gameId; public String gameName; public String getGameId() { return gameId; } public void setGameId(String gameId) { this.gameId = gameId; } public String getGameName() { return gameName; } public void setGameName(String gameName) { this.gameName = gameName; } }

fastjson将json格式字符串转成list集合

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