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自定义Popupwindow并指定显示位置!

2021-05-26 Windows程序

activity_popup_window_tooltip_text.xml

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent" android:layout_height="match_parent" android:paddingLeft="@dimen/activity_horizontal_margin" android:paddingRight="@dimen/activity_horizontal_margin" android:paddingTop="@dimen/activity_vertical_margin" android:paddingBottom="@dimen/activity_vertical_margin" tools:context="com.artshell.trainingdemos.test.PopupWindowTooltipTextActivity"> <Button android:id="@+id/anchor_view" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="Click me to see tooltip" android:layout_centerInParent="true"/> </RelativeLayout>

nav_up.xml (drawable)

<?xml version="1.0" encoding="utf-8"?> <layer-list xmlns:android="http://schemas.android.com/apk/res/android"> <item> <rotate android:fromDegrees="45" android:pivotX="-50%" android:pivotY="80%" android:toDegrees="45"> <shape android:shape="rectangle"> <solid android:color="#92e4e5"/> <stroke android:width="2dp" android:color="#92e4e5"/> </shape> </rotate> </item> </layer-list>

tooltip_bg.xml (drawable)

<?xml version="1.0" encoding="utf-8"?> <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle"> <solid android:color="#92e4e5"/> <stroke android:width="2dp" android:color="#92e4e5"/> <corners android:radius="2dp"/> </shape>

popup_window_tooltip_layout.xml

<?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:gravity="center" android:orientation="vertical"> <ImageView android:id="@+id/tooltip_nav_up" android:layout_width="25dp" android:layout_height="25dp" android:background="@drawable/nav_up"/> <TextView android:id="@+id/tooltip_text" android:layout_width="wrap_content" android:layout_height="wrap_content" android:background="@drawable/tooltip_bg" android:gravity="center" android:padding="10dp" android:text="Tooltip using PopupWindow :)" android:textColor="@android:color/white" android:textSize="20sp" android:textStyle="bold"/> </LinearLayout>

Activity代码:

public class PopupWindowTooltipTextActivity extends ActionBarActivity { private View contentView; private PopupWindow tipWindow; private Button anchor_view; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_popup_window_tooltip_text); anchor_view = (Button) findViewById(R.id.anchor_view); contentView = getLayoutInflater().inflate(R.layout.popup_window_tooltip_layout, null); tipWindow = new PopupWindow(this); tipWindow.setTouchInterceptor(new View.OnTouchListener() { @Override public boolean onTouch(View v, MotionEvent event) { if (event.getAction() == MotionEvent.ACTION_OUTSIDE) { tipWindow.dismiss(); } // 这个地方一定要返回false,你可能会说这里已经消费掉事件了啊应该返回true,参看PopupWindow的私有类PopupViewContainer // 弹出的View都是交由这个类来管理的,因为它对onTouchEvent()这个回调方法已经提供了一些默认实现,当你是返回true,事件就在此被拦截 // 不会再继续派发了,所以onTouchEvent()无法被调用 return false; } }); anchor_view.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { tipWindow.setWidth(ViewGroup.LayoutParams.WRAP_CONTENT); tipWindow.setHeight(ViewGroup.LayoutParams.WRAP_CONTENT); tipWindow.setOutsideTouchable(true); tipWindow.setTouchable(true); tipWindow.setFocusable(true); Bitmap bitmap = BitmapFactory.decodeResource(getResources(), R.drawable.easyicon_net); // 某些博客说,当没有设置Background的时候,无论是触摸其他空白区还是back键都无法dismiss()掉这个PopupWindow // 但我注释掉这段代码能dismiss(),有可能是个Bug,已经得google到修复 tipWindow.setBackgroundDrawable(new BitmapDrawable(getResources(),bitmap)); tipWindow.setContentView(contentView); // 计算这个PopupWindow的显示位置 int[] screen_pos = new int[2]; anchor_view.getLocationInWindow(screen_pos); Rect anchor_rect = new Rect(screen_pos[0], screen_pos[1], screen_pos[0] + anchor_view.getWidth(), screen_pos[1] + anchor_view.getHeight()); contentView.measure(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT); int contentViewWidth = contentView.getMeasuredWidth(); int contentViewHeight = contentView.getMeasuredHeight(); int position_x = anchor_rect.centerX() - (contentViewWidth / 2); int position_y = anchor_rect.bottom - (anchor_rect.height() / 2); tipWindow.showAtLocation(anchor_view, Gravity.NO_GRAVITY, position_x, position_y); } }); } }

还要注意一点就是:当你的已经dismiss()掉了,想再次显示PopupWindow,,那么它的某些属性需要重新设置,不能一处写好多处使用,参看这个dismiss()方法的源码实现。在没有dismiss()之前,你的PopupWindow内容发生变化了,你可以使用它的update()系列方法来更新.......


这里再帖连个参考链接,希望对你有所帮助

【Android PopupWindow的使用和分析】

【Popupwindow的使用】


自定义Popupwindow并指定显示位置!

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