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Throwing Balls into the Baskets 解题心得

2021-03-26 Windows程序

You probably have played the game "Throwing Balls into the Basket". It is a simple game. You have to throw a ball into a basket from a certain distance. One day we (the AIUB ACMMER) were playing the game. But it was slightly different from the main game. In our game we were N people trying to throw balls into identical Baskets. At each turn we all were selecting a basket and trying to throw a ball into it. After the game we saw exactly S balls were successful. Now you will be given the value of and M. For each player probability of throwing a ball into any basket successfully is P. Assume that there are infinitely many balls and the probability of choosing a basket by any player is 1/M. If multiple people choose a common basket and throw their ball, you can assume that their balls will not conflict, and the probability remains same for getting inside a basket. You have to find the expected number of balls entered into the baskets after Kturns.

Input

Input starts with an integer T (≤ 100), denoting the number of test cases.

Each case starts with a line containing three integers N (1 ≤ N ≤ 16), M (1 ≤ M ≤ 100) and K (0 ≤ K ≤ 100) and a real number P (0  P ≤ 1).P contains at most three places after the decimal point.

Output

For each case, print the case number and the expected number of balls. Errors less than 10-6 will be ignored.

Sample Input

2

1 1 1 0.5

1 1 2 0.5

Sample Output

Case 1: 0.5

Case 2: 1.000000

分析:

那个M完全没有用好吧,题目说这么长,完全就是在迷惑我们,,结果就是  double ans = n*p*k;

代码:

#include <stdio.h> #include <iostream> #include<cstdio> #include<iomanip> #include<cmath> using namespace std; int main() { int t; int kase = 0; cin >> t; int n, m, k; double p; while (t--) { kase++; cin >> n >> m >> k >> p; double ans = n*p*k; cout << "Case " << kase << :<< << fixed << setprecision(6) << ans << endl; } return 0; }

LightOJ1317---Throwing Balls into the Baskets 解题心得

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