c#提供了Intersect来得到两个列表的交集，它是通过使用默认的相等比较器对值进行比较生成两个序列的交集，定义为：

public static IEnumerable<TSource> Intersect<TSource>(this IEnumerable<TSource> first, IEnumerable<TSource> second);

我们使用它来比较两个列表试试：

List<double> oneList = new List<double> { 9, 8, 5, 3 }; List<double> twoList = new List<double> { 9, 3 }; List<double> result = oneList.Intersect(twoList).ToList();

结果是{9,3}

我们再来试试对象列表

我们先定义一个模型

public class TarGetValueList { public double TargetValue { get; set; } }

然后求交集

List<TarGetValueList> ListOne = new List<TarGetValueList>(); List<TarGetValueList> ListTwo= new List<TarGetValueList>(); //第一个列表增加的对象 TarGetValueList Night = new TarGetValueList() { TargetValue = 9.0 }; TarGetValueList Sex = new TarGetValueList() { TargetValue = 6.0 }; TarGetValueList Seven = new TarGetValueList() { TargetValue = 7.0 }; TarGetValueList Five = new TarGetValueList() { TargetValue = 5.0 }; //第二个列表增加的对象 TarGetValueList Three = new TarGetValueList() { TargetValue = 3.0 };//第一个列表增加对象 ListOne.Add(Night); ListOne.Add(Sex); ListOne.Add(Five); ListOne.Add(Seven);//9 6 5 7 //第二个列表增加对象 ListTwo.Add(Five); ListTwo.Add(Three); //5 3 List<TarGetValueList> resultList = ListTwo.Intersect(ListOne).ToList();

第一个列表是{9，6，5，7}，第二个列表是{5,3}，结果交集是{5}，结果在预想之内，至今为止，一切都很顺利。我们似乎已经掌握了用c#来求两个列表的交集，但让我们在以上的例子上进行以下的尝试：

List<TarGetValueList> ListOne = new List<TarGetValueList>(); List<TarGetValueList> ListTwo= new List<TarGetValueList>(); //第一个列表增加的对象 TarGetValueList Night = new TarGetValueList() { TargetValue = 9.0 }; TarGetValueList Sex = new TarGetValueList() { TargetValue = 6.0 }; TarGetValueList Seven = new TarGetValueList() { TargetValue = 7.0 }; TarGetValueList Five = new TarGetValueList() { TargetValue = 5.0 }; //第二个列表增加的对象 TarGetValueList Three = new TarGetValueList() { TargetValue = 3.0 }; TarGetValueList FiveTwo = new TarGetValueList() { TargetValue = 5.0 }; //第一个列表增加对象 ListOne.Add(Night); ListOne.Add(Sex); ListOne.Add(Five); ListOne.Add(Seven);//9 6 5 7 //第二个列表增加对象 ListTwo.Add(FiveTwo); ListTwo.Add(Three); //5 3 List<TarGetValueList> resultList = ListTwo.Intersect(ListOne).ToList();

第一个列表仍然是{9，6，5，，7}，第二个列表仍然是{5,3}，得到的结果交集列表却为空了。第二个列表的5跟第一个列表的5来自不同的对象，不过对象里的值都是一样的。但Intersect函数判断它们不是交集对象，这是因为判断对象是否相等是根据它们的内存地址来判断，那我们判断对象之间相等就没办法了吗？我们重写IEqualityComparer即可：

public class TarGetComparer : IEqualityComparer<TarGetValueList> { public bool Equals(TarGetValueList x, TarGetValueList y) { try { return x.TargetValue == y.TargetValue; } catch(Exception ex) { return base.Equals(x); } } public int GetHashCode(TarGetValueList obj) { return obj.TargetValue.GetHashCode(); } }

List<TarGetValueList> ListOne = new List<TarGetValueList>(); List<TarGetValueList> ListTwo= new List<TarGetValueList>(); //第一个列表增加的对象 TarGetValueList Night = new TarGetValueList() { TargetValue = 9.0 }; TarGetValueList Sex = new TarGetValueList() { TargetValue = 6.0 }; TarGetValueList Seven = new TarGetValueList() { TargetValue = 7.0 }; TarGetValueList Five = new TarGetValueList() { TargetValue = 5.0 }; //第二个列表增加的对象 TarGetValueList Three = new TarGetValueList() { TargetValue = 3.0 }; TarGetValueList FiveTwo = new TarGetValueList() { TargetValue = 5.0 }; //第一个列表增加对象 ListOne.Add(Night); ListOne.Add(Sex); ListOne.Add(Five); ListOne.Add(Seven);//9 6 5 7 //第二个列表增加对象 ListTwo.Add(FiveTwo); ListTwo.Add(Three); //5 3 List<TarGetValueList> resultList = ListTwo.Intersect(ListOne,new TarGetComparer()).ToList();

这样就得出了我们预期的结果{5}

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原文地址：https://www.cnblogs.com/ssvip/p/12103656.html